Total number of candidates appearing for JEE Main 2020 Below mentioned are the few factors which are mainly considered. Candidates should meet the authorised JEE Main 2020 cutoff to attempt the JEE Advanced examination for admission in IITs.Īscertain factors of JEE Main Cutoff 2020Ĭutoff marks will be decided on various factors. Here, JEE Main 2020 will need minimum marks which are to be scored and qualified for JEE Advanced. Basically, there are two different types of JEE Main 2020 cutoff, which is qualifying cutoff and admission cutoff. They will announce it only after the results are announced or before the counselling. NTA will release the cutoff for JEE Main 2020 in online mode. No deduction or addition in marks for leaving a question unattempted, for multiple answer questions(MCQ questions in which 2 or more options are correct) there are no negative marks. Marking Scheme for Numerical Type Questionsįor every correct answer you are rewarded 4 marks. This exam held in 2 different shifts.įor every correct answer you are rewarded 4 marks and a negative (-1) for a wrong answer. JEE Main 2020 exam conducted from 06 January 2020 to 09 January 2020. Unattempted questions do not have any deduction. To complete the paper, 3 hours will be allotted.Įach correct answer will be provided with 4 marks and for each incorrect answer, there will be a deduction of ¼ marks.Įvery question will have only one answer if multiple answers are marked, then it will be considered as an incorrect answer and ¼ marks will be deducted. USE Coupon Code: CJEE Click Here for Best JEE Crash Course JEE Mains 2020 Paper Exam Pattern: The first session was held in the month of January and followed by the second session in September. JEE Main 2020 conducted in two different sessions. JEE Main is the important qualifying exam for JEE Advanced depending on which admission will be provided into B.E/B.Tech programs offered at the Indian Institute of Technology (IIT). The oxidation number of sulphur in S8.JEE Main is conducted by National Testing Agency (NTA) for admission to undergraduate programs like Engineering (B.E/B.Tech) and Architecture (B.Arch/B.Planning) at IITs, NITs, Institutions funded by participating State Governments and other Centrally funded Technical Institutions (CFTI). One mole of calcium phosphide on reaction with excess water gives: Here JEE 1999 question is also available in English. You can get daily updates on JEE Main 1999 from here you can also check similar links for other related study materials on JEE Screening Entrance 1999 exam.

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